![]() Round to 2 decimal points DecimalFormat decimalFormat = new DecimalFormat("0.00") ĭtRoundingMode(RoundingMode.HALF_UP) Round to 1 decimal point DecimalFormat decimalFormat = new DecimalFormat("0.0") ĭtRoundingMode(RoundingMode.HALF_UP) Format Pattern “0.00” vs “#.#” DecimalFormat class allows us to create an output pattern and then set a rounding mode that we want to apply to a value. (bigDecimalFloatWithScale) // Prints 11.90Īnother way to round a float or a double value to 2 decimal points is to use the DecimalFormat class. (bigDecimalFloat) // Prints 11.89890003204345703125īigDecimal bigDecimalFloatWithScale = tScale(2, RoundingMode.HALF_UP) BigDecimal – Round float to 2 decimal points example import īigDecimal bigDecimalFloat = new BigDecimal(floatValue) Similarly, you can use BigDecimal to round a float value to 2 decimal points. BigDecimal – Round double to 2 decimal points example import īigDecimal bigDecimalDouble = new BigDecimal(doubleValue) RoundingMode.HALF_UP – is a rounding mode used.BigDecimal bigDecimalDouble = new BigDecimal(doubleValue) īigDecimal class allows us to set a scale and a rounding mode. One of the ways to round a float or a double value is to use BigDecimal class. Using String.format(“%.2f”, floatValue) 1. Decimal Format – Round float to 2 decimal points example.Decimal Format – Round double to 2 decimal points example.BigDecimal – Round float to 2 decimal points example.BigDecimal – Round double to 2 decimal points example.User Registration, Log in, Log out – Video Tutorials.Your problem is in how a double is stored because it is represented inīinary when provision in decimal exceeds the precision in the binary storage You need to use "floor" or "round" or convert to a long before converting to I assume that -1 would not be for your case. Was also under the impression that you could return a Null value for any in this case, return a negative value.Īlso, I have not tried to compile this code, so check for syntax errors. Do something here to signify that the String submitted was not a valid First, guarantee that you have a sufficient ammount of digits in the Supposed to return a double value of 0.01? If that is the case, then I The question I have now is if the string sends a value of "1", is it ![]() So, if the string value sent is 12345, the actual double value you want To make success inevitable, let's start by drawing a bunch of UMLĭiagrams! - Tom Copeland, Jakarta DeveloperĪh, now I understand what you meant by implicit decimal. > *Copyright (c) ITtoolbox and message author. > *Leave Group: mailto: *Need Subscription Help? mailto: *Terms of Use: http:/ Opens a new window / help/ termsofuse.htm ![]() > *Manage Subscriptions: http:/ Opens a new window / My. > *Archives: http:/ Opens a new window / g/ java-l.asp Please notify the sender by E-Mail at the address > received this communication in error, please do not distribute, and > confidential and exempt from disclosure under applicable law. > which it is addressed and may contain information that is privileged, > This E-Mail is intended only for the use of the individual or entity to > amt = Double.parseDouble((sVal.substring(0,(iLen-2)) + "." + This function gets called about 10000 times each run. > me some pointers on how to make this better? I am concerned about > better ways to do it in Java and I just don't know them. saying that I know there is probably tons > the inbound value is 2 decimal place implicit. ![]() At the same time I need to of course add the decimal > I am just learning Java and have a need to take a string value and > # View Group Archive: http:/ Opens a new window / / hrd.asp? i=747 > http:/ Opens a new window / / r/ hdr.asp? r=14395 > # Read today's most popular technical paper. Please notify the sender by E-Mail at the addressĭouble value = Double.parseDouble("12.345") Received this communication in error, please do not distribute, and delete Which it is addressed and may contain information that is privileged,Ĭonfidential and exempt from disclosure under applicable law. This E-Mail is intended only for the use of the individual or entity to This function gets called about 10000 times each run.Īmt = Double.parseDouble((sVal.substring(0,(iLen-2)) + ""."" + Me some pointers on how to make this better? I am concerned about memoryĪlso. saying that I know there is probably tons ofīetter ways to do it in Java and I just don't know them. The inbound value is 2 decimal place implicit. At the same time I need to of course add the decimal since I am just learning Java and have a need to take a string value and convert
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